Question

How do you factor `4n^2 + 68n + 250`?

Answer 1

Factor `f(n) = 4n^2 + 68n + 250`

Explanation:

`f(n) = 2y = 2(2n^2 + 34n + 125).`
Factor `y = 2n^2 + 34n + 125`
`D = b^2 - 4ac = 1156 - 4000 = -2844 < 0`. Since its D < 0, this trinomial y can't be factored.
Finally, `f(n) = 2(2n^2 + 34n + 125)`