How do you factor #4t^2+4t+1#?

1 Answer
peter k.
Mar 9, 2018

#(2t+1)(2t+1)#

Explanation:

we are given:-

#4t^2+4t+1# resembles #ax^2+bx+c#
here #a=4,b=4 and c=1#
and since, sum#=b#,product#=ac#

factors are the number which when you (multiply) and also when you (add) them give the same value for sum and product.

sum=4
product=4*1=4
factors=2 and 2

so
#4t^2+2t+2t+1#
#2t(2t+1)+1(2t+1)#

#(2t+1)(2t+1)#

Related questions
See all questions in Factorization of Quadratic Expressions
Impact of this question
7601 views around the world
You can reuse this answer
Creative Commons License