# How do you factor #(4x^2+16x+15)/(2x^2+x-3)#?

##### 1 Answer

Mar 30, 2016

#### Explanation:

Call

Factor g(x) by the new AC Method to factor trinomials (Socratic)

Converted trinomial g'(x) = x^2 + 16 x + 60 = (x + p')(x + q')

Factor pairs od (6)) -->... (5, 12)(6, 10). This sum is 16 = b. Then p' = 6 and q' = 10.

Back to g(x) -->

Factor h(x) = 2x^2 + x - 3

Since a + b + c = 0, use shortcut. One factor is (x - 1) and the other is

Finally,