How do you factor #4x^2 + 24x + 36#?

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Answer 1 · 2018-03-08T00:15:12

#4(x+3)(x+3)#

First, factor out four from each of the elements:

#4(x^2+6x+9)#

Then find factors of the last and first elements that when added make the middle one:

#3 times 3 = 9" "# and #" "3+3 = 6#

#=>4(x^2+3x+3x+9)#

#=>4(x(x+3)+3(x+3))#

#=>4(x+3)(x+3)#