How do you factor #4x^2-4x+1#?

1 Answer
May 3, 2016

This is a perfect square trinomial:

#4x^2-4x+1 = (2x-1)^2#

Explanation:

One way of quickly spotting this (and a few more) factorisations is the pattern: #4, 4, 1#. The number #441# is the square of #21#, with no carried digits.

Hence we find:

#4x^2+4x+1 = (2x+1)^2#

and:

#4x^2-4x+1 = (2x-1)^2#