How do you factor #4x^2+4x+1#?
1 Answer
May 13, 2017
Explanation:
#"'split 4x into " 2x+2x#
#rArr4x^2+2x+2x+1#
#"factorise each 'pair'""#
#color(red)(2x)(2x+1)color(red)(+1)(2x+1)#
#"take out the common factor " (2x+1)#
#(2x+1)(color(red)(2x+1))#
#rArr4x^2+4x+1#
#=(2x+1)(2x+1)=(2x+1)^2#
