# How do you factor 4y² +11y-3?

Aug 9, 2015

$\left(4 y - 1\right) \left(y + 3\right)$

#### Explanation:

Note 3 is a prime number so only has factors 3 and 1. 4 can have factors 2 and 2 or 4 and 1, therefore the factorisation will likely be of the form:

$\left(2 y \pm 3\right) \left(2 y \pm 1\right)$

or

$\left(4 y \pm \left(3 , 1\right)\right) \left(y \pm \left(3 , 1\right)\right)$

In the second case by inspection we see that:

$4 {y}^{2} + 11 y - 3 = \left(4 y - 1\right) \left(y + 3\right)$