How do you factor #5x^2 +29x - 6#?

1 Answer
George C.
May 14, 2016

#5x^2+29x-6=(5x-1)(x+6)#

Explanation:

Use an AC method:

Find a pair of factors of #AC=5*6=30# with difference #B=29#.

The pair #30, 1# works.

Use that pair to split the middle term and factor by grouping:

#5x^2+29x-6#

#=5x^2+30x-x-6#

#=(5x^2+30x)-(x+6)#

#=5x(x+6)-1(x+6)#

#=(5x-1)(x+6)#

Related questions
See all questions in Factorization of Quadratic Expressions
Impact of this question
4607 views around the world
You can reuse this answer
Creative Commons License