How do you factor #64y^2 + 80y + 25#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Binayaka C. May 6, 2016 #(8y+5)^2# Explanation: #64y^2+80y+25= 64y^2+40y+40y+25=8y(8y+5)+5(8y+5)=(8y+5)(8y+5)=(8y+5)^2#[Ans] Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 2065 views around the world You can reuse this answer Creative Commons License