How do you factor #6a^2-21a+15#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Binayaka C. Apr 12, 2016 #3(a-1)(2a-5)# Explanation: #6a^2-21a+15=3(2a^2-7a+5)=3(2a^2-2a-5a+5)=3{2a(a-1)-5(a-1)})=3(a-1)(2a-5)#[Ans] Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 1480 views around the world You can reuse this answer Creative Commons License