Question

How do you factor `6g^2 + 11g - 35`?

Answer 1

`(2g+7)(3g-5)`

Explanation:

By splitting the middle term 11g as 21g- 10g, this can be factorised as follows:

`6g^2 +21g-10g -35=0`

#3g(2g+7)-5(2g+7)=0

`(2g+7)(3g-5)`