How do you factor #6p^2+5p-6#?

1 Answer
George C.
May 10, 2016

#6p^2+5p-6=(3p-2)(2p+3)#

Explanation:

Use an AC method:

Find a pair of factors of #AC = 6*6 = 36# which differ by #B=5#

The pair #9, 4# works, in that #9xx4=36# and #9-4=5#.

Use this pair to split the middle term and factor by grouping:

#6p^2+5p-6#

#=6p^2+9p-4p-6#

#=(6p^2+9p)-(4p+6)#

#=3p(2p+3)-2(2p+3)#

#=(3p-2)(2p+3)#

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