How do you factor #6t^2+26t+24#?

1 Answer
Mar 25, 2018

#6t^2+26t+24=2(3t+4)(t+3)#

Explanation:

First we can factoring with 2.
[0]#6t^2+26t+24=2(3t^2+13t+12)#
Then you can say that #13t# is #9t+4#, and you can factoring again.
[1]#6t^2+26t+24=2(3t^2+9t+4t+12)#
[2]#6t^2+26t+24=2(3t*(t+3)+4(t+3))#
[3]#6t^2+26t+24=2(3t+4)(t+3)#
You can do it faster if you know how to do an euclidiean division of a polynomial :)