How do you factor #6x^2+19x+15#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Konstantinos Michailidis Sep 25, 2015 Refer to explanation Explanation: We have that #6x^2+19x+15=6x^2+10x+9x+15=2x*(3x+5)+3*(3x+5)=(2x+3)*(3x+5)# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 9131 views around the world You can reuse this answer Creative Commons License