How do you factor #6x^2 - 28x + 16#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Nicole May 21, 2016 #(6x-4)(x-4)# Explanation: #6x^2-28x+16# #(6x-4)(x-4)# From this you can solve for #x# #x=4# #x=2/3# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 2250 views around the world You can reuse this answer Creative Commons License