How do you factor #-6x^2+31x-35#?

1 Answer
jeffwwally
Mar 3, 2017

#(3x-5)(2x-7)#

Explanation:

I started by factoring out a negative one.
#-6x^2+31x-35#
#-1(6x^2-31x+35)#

From there, you can split the middle term to accommodate both terms and get the same internal expression. (Some guess and check involved)
#6x^2-21x-10x+35#
#3x(2x-7)-5(2x-7)#

From there you combine them to get
#(3x-5)(2x-7)#
and there is your factored form.

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