How do you factor #7c^2-16c+9#?
1 Answer
May 2, 2016
Explanation:
Notice that
#7c^2-16c+9#
#= 7c^2-7c-9c+9#
#= (7c^2-7c)-(9c-9)#
#= 7c(c-1)-9(c-1)#
#= (7c-9)(c-1)#
Notice that
#7c^2-16c+9#
#= 7c^2-7c-9c+9#
#= (7c^2-7c)-(9c-9)#
#= 7c(c-1)-9(c-1)#
#= (7c-9)(c-1)#