How do you factor #7k^2+19k+10#?

1 Answer
Apr 5, 2016

Look for factor pairs of #7# and of #10# which when cross multiplied equal #19#.
This should allow you to find:
#color(white)("XXX")(k+2)(7k+5)#

Explanation:

Note that since all terms in the given expression are positive, we only need to consider positive factors.

Factors of #7#
#color(white)("XXX"){color(red)(color(white)("")(1,7))}#
Factors of #10#
#color(white)("XXX"){color(blue)(color(white)("")(1,10),(2,5))}#

Using #" X "# to indicate cross multiplication:
Since #color(red)(1)xxcolor(blue)(5)+color(red)(7)xxcolor(blue)(2) = 19#

#color(white)("XXX"){:(color(red)(1)),(color(red)(7)):}" X "{:(color(blue)(2)),(color(blue)(5)):}=19#

The required factors are
#color(white)("XXX")(color(red)(1)k+color(blue)(2))(color(red)(7)k+color(blue)(5))#

Note that this method only works since the coefficients are integer.