How do you factor #8x^2-10xy+3y^2#?

1 Answer
Oct 16, 2015

Factor: #f(x, y) = 8x^2 - 10xy + 3y^2#

Ans: (2x - y)(4x - 3y)

Explanation:

Find 2 numbers p and q, knowing (pq) = 24 and (p + q) = -10. They are -4 and -6. Replace the term -10xy by the 2 terms -4xy and - 6xy.
#f(x, y) = 8x^2 - 4xy - 6xy + 3y^2.#
f(x, y) = 4x(2x - y) - 3y(2x - y)
f(x. y) = (2x - y)(4x - 3y)
Check by developing:
#8x^2 - 6xy - 4xy + 3y^2 = 8x^2 - 10xy + 3y^2.# OK