How do you factor #9(x+4)^2+12(x+4)+4#?

1 Answer
Mar 31, 2018

#9(x+4)^2+12(x+4)+4 =color(blue)((3x+14)^2)#

Explanation:

You could expand each of the terms and then collect like terms before attempting to factor, but it is probably easier to temporarily substitute a variable for #(x+4)#; for example with #k=x+4# we would have:

# 9k^2+12k+4#

which factors fairly easily into #(3k+2)^2#

then replacing the #k# with #x+4#
we get #(3(x+4)+2)^2=(3x+14)^2#