How do you factor #9x^2+12x+4#?

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Answer 1 · 2018-05-03T17:03:40

#=>(3x+2)^2#

#9x^2+12x+4#

This is a perfect square trinomial of the form:

#a^2x^2 + bx + c^2#

This means its factorization is:

#(ax+c)^2#

In our case, we have #a = 3#, #b = 12#, and #c = 2#. So we have:

#9x^2 + 12x +4 = (3x+2)^2#