How do you factor #9x²-6x-15#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Konstantinos Michailidis Jun 26, 2016 Notice that #15=9+6# hence #9x^2-6x-(9+6)=9x^2-9-6x-6=9(x^2-1)-6(x+1)= 9(x-1)(x+1)-6(x+1)=(x+1)(9x-9-6)=(x+1)(9x-15)= 3(x+1)(3x-5)# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 1534 views around the world You can reuse this answer Creative Commons License