How do you factor #9y^2(8b-c)-2x^2(c -8b)#?
1 Answer
Feb 27, 2016
Explanation:
Take out -1 as a common factor in the bracket (c - 8b ). This will make it in the same form as (8b - c ) and then use as common factor.
hence
#- 2x^2(-1)(8b - c )# then
#9y^2(8b - c ) + 2x^2(8b - c ) = (8b - c )(9y^2 + 2x^2 )#
