# How do you factor and solve 2x^2-6x+4=0?

Aug 5, 2016

$x = 1 \mathmr{and} x = 2$

#### Explanation:

Notice that all the coefficients are even.
We can therefore divide by 2 to simplify matters.

$2 {x}^{2} - 6 x + 4 = 0 \text{ } \div 2$

${x}^{2} - 3 x + 2 = 0 \text{ }$ Find the factors of 2 which add up to 3.

$\left(x - 2\right) \left(x - 1\right) = 0$

Each factor could be equal to 0.
$x - 2 = 0 \Rightarrow x = 2$

$x - 1 = 0 \Rightarrow x = 1$