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How do you factor and solve #2x^2 + x - 1=0#?

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27
Jan 15, 2017

Answer:

#x=1/2# or #x=-1#

Explanation:

#2x^2+x-1=0#

Factorise.

#2x^2+2x-x-1=0#

#2x(x+1)-1(x+1)=0#

#(2x-1)(x+1)=0#

#2x-1=0# or #x+1=0#

#x=1/2# or #x=-1#

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