# How do you factor and solve #2y^2 +7y + 3 =0#?

##### 1 Answer

Factor is

Solving;

#### Explanation:

First, make sure the equation is in the standard form

**a #x^2# + bx + c = 0**

If

In this case,

What is the **ac method**???

The ac method is simply the value of a times the value of c

**Now we have to find the numbers that will give a product of 6 as well as a sum of 7.**

Bingo! Now that we have these numbers, we rewrite the equation substituting

**2 #y^2# + y + 6y + 3 = 0** ...this is the same as the inital equation when simplified.

**Now, we factor by grouping and pulling out the gcf** .

**Solve for y**

**Dividing both sides by 2, we get**

**Solve the other also for y**