How do you factor and solve #2y^2 +7y + 3 =0#?
First, make sure the equation is in the standard form
In this case,
What is the ac method???
The ac method is simply the value of a times the value of c
Now we have to find the numbers that will give a product of 6 as well as a sum of 7.
Bingo! Now that we have these numbers, we rewrite the equation substituting
Now, we factor by grouping and pulling out the gcf .
Solve for y
Dividing both sides by 2, we get
Solve the other also for y