How do you factor and solve #6x^2 - 53x -9 =0#?

1 Answer
Robert C.
Jun 4, 2016

(6x + 1)(x - 9) = 0

Explanation:

since you have a number greater then 1 at the #x^2# you would multiply that by -9 (the last digit in the equation) and arrive at -54. then you need two numbers that add to -53 and multiply to -54. the only two numbers that satisfy this are 1 and -54.

group the equation so that you can factor it further

#6x^2-54x+x-9=0#

#6x(x-9) +1(x-9)=0#

#(6x+1)(x-9)=0#

Related questions
See all questions in Comparing Methods for Solving Quadratics
Impact of this question
1359 views around the world
You can reuse this answer
Creative Commons License