How do you factor and solve 6x^2 - 53x -9 =0?

Jun 4, 2016

(6x + 1)(x - 9) = 0

Explanation:

since you have a number greater then 1 at the ${x}^{2}$ you would multiply that by -9 (the last digit in the equation) and arrive at -54. then you need two numbers that add to -53 and multiply to -54. the only two numbers that satisfy this are 1 and -54.

group the equation so that you can factor it further

$6 {x}^{2} - 54 x + x - 9 = 0$

$6 x \left(x - 9\right) + 1 \left(x - 9\right) = 0$

$\left(6 x + 1\right) \left(x - 9\right) = 0$