# How do you factor and solve  r^3 + 3r^2 + 3r + 1 = 0?

Jan 12, 2017

r = -1

#### Explanation:

$f \left(r\right) = {r}^{3} + 3 {r}^{2} + 3 r + 1 = 0$
Use algebra identity:
${\left(r + 1\right)}^{3} = {r}^{3} + 3 {r}^{2} + 3 r + 1$
$f \left(r\right) = {\left(r + 1\right)}^{3}$