How do you factor and solve #x^2+2x8=0#?
2 Answers
The solutions for the equation are
Explanation:
We can Split the Middle Term of this expression to factorise it.
In this technique, if we have to factorise an expression like
AND
After trying out a few numbers we get

#color(blue)(x2) =0 , color(blue)(x=2 # 
#color(blue)(x + 4) =0 , color(blue)(x=4#
2 and 4
Explanation:
Solve
The 2 real roots have opposite signs because ac < 0
Find 2 real roots knowing sum (b = 2) and product (c = 8).
Factor pairs of (c = 8) > (2, 4)(2, 4). This last sum is (2 = b).
Therefor, the 2 real roots are: 2 and 4.