# How do you factor and solve x^2+4x-3=0?

Jan 5, 2018

It doesn't factorise but it can still be solved, for example : By completing the square.

#### Explanation:

So let's complete the square.

$\therefore$ ${x}^{2} + 4 x - 3 = {\left(x + 2\right)}^{2} - 4 - 3 = 0$
$\therefore {\left(x + 2\right)}^{2} - 7 = 0$

Now lets solve:

${\left(x + 2\right)}^{2} - 7 = 0$
${\left(x + 2\right)}^{2} = 7$
$x + 2 = \pm \sqrt{7}$
$x = - 2 \pm \sqrt{7}$

Therefore X has been solved

$x = - 2 + \sqrt{7}$ or $x = - 2 - \sqrt{7}$