# How do you factor and solve x^2+4x+4=0 ?

Sep 19, 2016

$x = - 2$

#### Explanation:

We have: ${x}^{2} + 4 x + 4 = 0$

Let's factorise this equation using the middle-term break:

$\implies {x}^{2} + 2 x + 2 x + 4 = 0$

$\implies x \left(x + 2\right) + 2 \left(x + 2\right) = 0$

$\implies \left(x + 2\right) \left(x + 2\right) = 0$

$\implies {\left(x + 2\right)}^{2} = 0$

$\implies x + 2 = 0$

$\implies x = - 2$

Therefore, the solution to the equation is $x = - 2$.