How do you factor #b^2+16b+64#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer George C. May 15, 2015 That #64 = 8*8# and #16 = 8+8# is a bit of a give away: #(b+8)^2 = (b+8)(b+8)# #= b*b + 8b + 8b + 8*8 = b^2 + 16b + 64# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 5050 views around the world You can reuse this answer Creative Commons License