How do you factor $g^2-9$ ?

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Answer 1 · 2015-11-02T12:38:24

The factorised form for the expression is:
$color(green)((g+3)(g-3)$

As per property:
$color(green)(a^2-b^2=(a+b)(a-b)$

Applying the above to the expression provided:

$g^2-9=g^2-3^2$

Here, $color(green)(a)=g, color(green)(b)=3$

So,
$g^2-9=color(green)((g+3)(g-3)$

How do you factor g^2-9 g^2-9 ?