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How do you factor ${(m + n)}^{2} - p^{4}$ $(m+n)^2 - p^4$ ?

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Konstantinos Michailidis

Oct 8, 2015

It is ${(m + n)}^{2} - p^{4} = (m + n + p^{2}) \cdot (m + n - p^{2})$ $(m+n)^2-p^4=(m+n+p^2)*(m+n-p^2)$

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