Question

How do you factor `n^2-11np-80p^2`?

Answer 1

(n + 5p)(n - 16p)

Explanation:

Consider n as variable and p as constant, then factor the quadratic function
`f(n) = n^2 - 11p.n - 80 p^2`
Find 2 numbers , with opposite signs, having sum (-11p) and product
(-80p^2).
Factor pairs of (-80p^2) -->... (-2p, 40p)(-5p, 16p)(5p, -16p). This sum is (-11p) = b. Therefor, the 2 numbers are 5p and -16p
y = (n + 5p)(n - 16p)