How do you factor #n^2+6n+8#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer George C. May 30, 2015 Notice that #4 + 2 = 6# and #4 xx 2 = 8# So #(n+4)(n+2) = n^2+(4+2)n+(4xx2)# #= n^2+6n+8# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 3259 views around the world You can reuse this answer Creative Commons License