How do you factor #s^2+4s-12#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Konstantinos Michailidis Sep 25, 2015 It is #s^2+4s-12=s^2+4s+4-16=(s+2)^2-4^2=(s+2+4)*(s+2-4)=(s+6)*(s-2)# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 1606 views around the world You can reuse this answer Creative Commons License