Question

How do you factor `sin^2(x) + sin x - 2`?

Answer 1

We have that

#sin^2(x) + sin x - 2=sin^2x+sinx-1-1= (sin^ 2x-1)+(sinx-1)=(sinx-1)*(sinx+1)+(sinx-1)= (sinx-1)*(sinx+2)#