How do you factor the expression #15m^2 + 20mp - 12mp - 16p^2#?

1 Answer
May 13, 2016

#15m^2+20mp-12mp-16p^2=(5m-4p)(3m+4p)#

Explanation:

Factor by grouping:

#15m^2+20mp-12mp-16p^2#

#=(15m^2+20mp)-(12mp+16p^2)#

#=5m(3m+4p)-4p(3m+4p)#

#=(5m-4p)(3m+4p)#

#color(white)()#
Footnote

Note that the hard/fun part of the problem has already been done for you.

Normally you would be asked to factor something like:

#15m^2+8mp-16p^2#

It would then be up to you to find the right split of #8mp# as #20mp-12mp# to get the factoring by grouping to work.

To help with that, you could use an "AC method":

Ignoring signs, the three coefficients of the quadratic are:

#A=15#, #B=8# and #C=16#.

Noting that the sign on the last term is negative, you then look for a factorisation of #AC = 15*16 = 240# into a product of two numbers whose difference is #B=8#. If the sign on the last term was positive, then you would look for a pair of factors whose sum was #B#.

With a little thinking, experimentation, searching and/or trial and error, you can find the pair #20, 12# which satisfies the requirements: #20xx12 = 240# and #20-12 = 8#.

Then you would replace #8mp# with #20mp - 12mp# before factoring by grouping.