How do you factor the expression #18r^2 + 12ry - 3xr - 2xy#?
1 Answer
Apr 5, 2016
(3r + 2y)(6r - x)
Explanation:
group the terms into 2 'pairs'
hence: [
#18r^2 + 12ry ] + [ -3xr - 2xy ]# now factor each pair:
6r(3r + 2y) - x(3r + 2y)
There is a common factor of (3r + 2y) in each pair.
thus : (3r + 2y )(6r - x)
