How do you factor the expression 21x^2+29x-10?

Mar 1, 2016

(3x+5) & (7x-2)

Explanation:

$21 {x}^{2} + 29 x - 10$

$21 {x}^{2} + 35 x - 6 x - 10$

$7 x \left(3 x + 5\right) - 2 \left(3 x + 5\right)$

$\left(3 x + 5\right) \left(7 x - 2\right)$

$\therefore$ Factors of above equation are $3 x + 5$ and $7 x - 2$.