How do you factor the expression #2x^2-9x-5#?

1 Answer
May 12, 2018

#(2x+1)(x-5)#

Explanation:

#"using the a-c method to factorise the quadratic"#

#"the factors of the product "2xx-5=-10#

#"which sum to - 9 are - 10 and + 1"#

#"split the middle term using these factors"#

#2x^2-10x+x-5larrcolor(blue)"factor by grouping"#

#=color(red)(2x)(x-5)color(red)(+1)(x-5)#

#"take out the "color(blue)"common factor "(x-5)#

#=(x-5)(color(red)(2x+1))#

#rArr2x^2-9x-5=(x-5)(2x+1)#