How do you factor the expression #3x^2 - 7x + 2#?

1 Answer
Aug 5, 2016

(3x - 1)(x - 2)

Explanation:

Use the new AC Method (Socratic Search)
#y = 3x^2 - 7x + 2 =# 3(x + p)(x + q)
Converted trinomial: #y' = x^2 - 7x + 6.=# (x + p')(x + q')
Factor pairs of (ac = 6) --> (-1, -6). Then, p' = -1 and q' = -6.
Back to y --> #p = (-p')/a = -1/3# and #q = (q')/a = -6/3 = -2#
Factoring of y:
#y = 3(x - 1/3)(x - 2) = (3x - 1)(x - 2)#