We start with #3x^2-7x-6#. In order to factor this, we need to find the numbers that add to -7 and multiply to -18. I found #2# and #-9# to be the only solution for those parameters. Now, we factor by grouping, like this:
#(3x^2+color(white)(..))(color(white)(..)-6)#, which we fill in the blank spaces with the #2# and #-9#.
#(3x^2-9x)(2x-6)#, which we can factor to become #3x(x-3)# and #2(x-3)#. we can simplify these expressions to be only #(3x+2)(x-3)#.