How do you factor the expression #4r^2-40r+96 #?

1 Answer
May 29, 2017

#4r^2-40r+96 = 4(r-6)(r-4)#

Explanation:

Note that all of the given terms are divisible by #4#, so separate that out as a factor first then complete the square:

#4r^2-40r+96 = 4(r^2-10r+24)#

#color(white)(4r^2-40r+96) = 4(r^2-10r+25-1)#

#color(white)(4r^2-40r+96) = 4((r-5)^2-1^2)#

#color(white)(4r^2-40r+96) = 4((r-5)-1)((r-5)+1)#

#color(white)(4r^2-40r+96) = 4(r-6)(r-4)#