How do you factor the expression #4r^2-40r+96 #?
1 Answer
May 29, 2017
Explanation:
Note that all of the given terms are divisible by
#4r^2-40r+96 = 4(r^2-10r+24)#
#color(white)(4r^2-40r+96) = 4(r^2-10r+25-1)#
#color(white)(4r^2-40r+96) = 4((r-5)^2-1^2)#
#color(white)(4r^2-40r+96) = 4((r-5)-1)((r-5)+1)#
#color(white)(4r^2-40r+96) = 4(r-6)(r-4)#