How do you factor the expression #4x^2-1#?

1 Answer
Dec 19, 2015

Apply the difference of squares formula to find that
#4x^2-1 = (2x+1)(2x-1)#

Explanation:

The difference of squares formula states that
#a^2 - b^2 = (a+b)(a-b)#
(Verify this by expanding the right hand side)

Applying this to the given problem, we have

#4x^2-1 = (2x)^2 - 1^2 = (2x+1)(2x-1)#