How do you factor the expression #4x^2 - 25#?

1 Answer
Feb 10, 2017

See the entire explanation below:

Explanation:

This expression is in the form:

#a^2x^2 - b^2# and can be factored to:

#(sqrt(a^2x^2) - sqrt(b^2))(sqrt(a^2x^2) + sqrt(b^2))#

Substituting the values from the problem gives:

#4x^2 - 25 = 2^2x^2 - 5^2 = (sqrt(2^2x^2) - sqrt(5^2))(sqrt(2^2x^2) + sqrt(5^2)) = #

#(2x - 5)(2x + 5)#