How do you factor the expression #5x^2+7x+2#?
1 Answer
Feb 25, 2016
(x + 1 )(5x + 2 )
Explanation:
The standard form of the quadratic function is
# ax^2 + bx + c# To factor , begin by considering the factors of the product ac , which also sum to give b , the coefficient of the x term.
in this question a = 5 , b = 7 and c = 2
hence:
#ac = 5xx2 =10 " whose factors are ±(1,2,5,10)"# The 'pair' are 5 and 2 as 5 + 2 = 7 = b
Now, rewrite the expression , replacing 7x by 5x + 2x
hence :
#5x^2 + 7x + 2 = 5x^2 + 5x + 2x + 2 # Factor the pairs :
#[5x^2 +5x ] " and " [2x + 2 ]#
#5x^2 + 5x = 5x(x + 1 ) " and " 2x + 2 = 2(x +1)# Finally , 'take out' the common factor (x + 1)
hence: (x +1)(5x + 2 )
#rArr 5x^2 + 7x + 2 = (x + 1 )(5x + 2 )#