How do you factor the expression #6x^2 - 33x + 15#?

1 Answer
Apr 23, 2016

#3(2x^2 - 11x + 5)#

Explanation:

Here, I divided every set of numbers by #3#. This means the #3# should go on the outside of the brackets that you need to put in when factorising expressions.

When #6x^2# is divided by #3#, it gives #2x^2#. This goes at the beginning of the brackets.

When #-33x# is divide by #3#, it gives #-11x#. This is put next to the #2x^2#.

Finally, to finish off factorising, #+15# divided by #3# gives #+5#.

Write out the answers that you have worked out:

#3(2x^2 - 11x + 5)#