How do you factor the expression #6x^2+7x+2#?

1 Answer
Feb 27, 2016

y = (2x + 1)(3x + 2)

Explanation:

Use the new AC Method to factor trinomial. (Socratic Search)
#y = 6x^2 + 7x + 2 = #6(x + p)(x + q)
Converted trinomial: #y' = x^2 + 7x + 12#
Factor pairs of 12 --> (3, 4). This sum is 7 = b.
#p= 3/6 = 1/2# and #q = 4/6 = 2/3.#
Factored form: #y = 6(x + 1/2)(x + 2/3) = (2x + 1)(3x + 2)#